Question

70 cm 3 of 0.01M Ca(OH)₂was added to a sample of water containing 0.001 moles of calcium hydrogen carbonate. Write an equation for the reaction which took place.

a. Ca(OH)₂+CO₂→CaCO₃+H₂O
b. Ca(OH)₂+Ca(HCO₃)₂→2CaCO₃+2H₂O
c. CaCO₃+CO₂→Ca(HCO₃)₂
d. Not Mentioned

Answer 1

The equation for the reaction is Ca(OH)₂+CO₂→CaCO₃+H₂O.

Step-by-step explanation:

The correct equation for the reaction is: a. Ca(OH)₂+CO₂→CaCO₃+H₂O. When 70 cm3 of 0.01M Ca(OH)₂ is added to a sample of water containing 0.001 moles of calcium hydrogen carbonate, the Ca(OH)₂ reacts with the CO₂ to form CaCO₃ and H₂O.