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What mass of copper will be deposited from a CuSO₄ solution by a current of 1.0 ampere flowing for 2 hours? (Atomic mass of Cu = 64.0, and 1 faraday = 96,500 C)

A. 3.2 g
B. 6.4 g
C. 9.6 g
D. 12.8 g

1 Answer

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Final answer:

To find the mass of copper deposited from a CuSO4 solution, we need to apply Faraday's law of electrolysis. Using the given values of current, time, atomic mass of copper, number of moles of electrons, and Faraday's constant, we can calculate the mass of copper deposited as 6.4 g.

Step-by-step explanation:

To calculate the mass of copper deposited from a CuSO4 solution, we need to use Faraday's law of electrolysis. According to this law, the mass of a substance deposited at an electrode is directly proportional to the amount of charge passed through the electrolyte. The formula to calculate the mass of the substance is:

Mass = (Current × Time × Atomic mass of substance) / (Number of moles of electrons × Faraday's constant)

In this case, the current is 1.0 ampere, the time is 2 hours, the atomic mass of copper is 64.0, the number of moles of electrons is 2 (since 2 electrons are required to reduce a single Cu²+ ion), and Faraday's constant is 96,500 C. Substituting these values into the formula, we get:

Mass = (1.0 A × 2 h × 3600 s/h × 64.0 g/mol) / (2 mol × 96,500 C)

Mass = 6.4 g

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