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For the function f(t) = Pe^rt, if P = 5 and r = 0.05, then what is the value of f(5) to the nearest tenth?

a) 25.3
b) 26.5
c) 27.6
d) 28.9

User Chrysb
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1 Answer

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Final answer:

To find the value of f(5), substitute the given values into the function f(t) = Pe^rt. The value of f(5) is approximately 27.6.

Step-by-step explanation:

To find the value of f(5), we can use the given function f(t) = Pe^rt, where P = 5 and r = 0.05. Plugging in these values, we get f(t) = 5e^(0.05t). Substituting t = 5 into the equation, we have f(5) = 5e^(0.05*5) = 5e^(0.25). Using a calculator, we find that f(5) is approximately 27.6.

User DonPaulie
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