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Using dismals tested, in which of the following numbers are visible by 6?

a) 24
b) 32
c) 36
d) 48

User Lsmor
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1 Answer

6 votes

Final answer:

Using divisibility rules for 6, the numbers 24, 36, and 48 are divisible by 6 because they are even and the sum of their digits is divisible by 3.

Step-by-step explanation:

The question is asking to identify which of the provided numbers are divisible by 6. A number is divisible by 6 if it is divisible by both 2 and 3. To test if a number is divisible by 2, it must be an even number (its last digit is 0, 2, 4, 6, or 8). To test if a number is divisible by 3, the sum of its digits must be divisible by 3.

  • a) 24 is even and the sum of its digits (2 + 4) equals 6, which is divisible by 3. Hence, 24 is divisible by 6.
  • b) 32 is even, but the sum of its digits (3 + 2) equals 5, which is not divisible by 3. Therefore, 32 is not divisible by 6.
  • c) 36 is even and the sum of its digits (3 + 6) equals 9, which is divisible by 3. Thus, 36 is divisible by 6.
  • d) 48 is even and the sum of its digits (4 + 8) equals 12, which is divisible by 3. Accordingly, 48 is divisible by 6.

In conclusion, the numbers 24, 36, and 48 are divisible by 6.

User Frederico
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