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How many of the following are found in 15.0 kmol of xylene (C6H6)?

(a) kg C6H6;
(b) mol C6H6;
(c) lb-mole C6H6;
(d) mol (g-atom) C;
(e) mol H;
(f) g C; (g) g H;
(h) molecules of C6H6​.

User Bukowski
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1 Answer

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Final answer:

In 15.0 kmol of xylene (C6H6), there are approximately 0.6249 kg of xylene, 9.033 × 10^24 mol of xylene, 6803.886 lb-mole of xylene, 7.2264 × 10^25 mol of carbon (g-atom), 9.033 × 10^25 mol of hydrogen, 8.677 × 10^26 g of carbon, 9.099 × 10^26 g of hydrogen, and 5.442 × 10^48 molecules of C6H6.

Step-by-step explanation:

To determine the quantities of each component in 15.0 kmol of xylene, we need to consider the chemical formula of xylene, which is C8H10.

  1. a) To find the mass of xylene in kg, we can use the molar mass of xylene: (8 mol C6H6)(78.1139 g/mol) = 624.9112 g C6H6. Converting grams to kg, we have 624.9112 g ÷ 1000 = 0.6249 kg C6H6.
  2. b) To determine the number of moles of xylene, we can use the formula: n = N × Avogadro's number, where N is the number of kmol and Avogadro's number is 6.022 × 10^23 mol^-1. Thus, (15.0 kmol)(6.022 × 10^23 mol^-1) = 9.033 × 10^24 mol C6H6.
  3. c) To convert kmol to lb-mole, we can use the conversion factor 1 lb-mole = 453.5924 mol. Therefore, (15.0 kmol)(453.5924 mol/lb-mole) = 6803.886 mol C6H6.
  4. d) The number of moles of g-atom C is equal to the number of moles of xylene multiplied by the number of atoms of C in xylene's molecular formula: (9.033 × 10^24 mol)(8) = 7.2264 × 10^25 mol.
  5. e) In the same way as part d, we can calculate the number of moles of H in xylene: (9.033 × 10^24 mol)(10) = 9.033 × 10^25 mol.
  6. f) To find the mass of carbon, we can use the molar mass of carbon and the number of moles of C in xylene: (7.2264 × 10^25 mol)(12.0107 g/mol) = 8.677 × 10^26 g C.
  7. g) Similar to part f, we can determine the mass of hydrogen: (9.033 × 10^25 mol)(1.00784 g/mol) = 9.099 × 10^26 g H.
  8. h) To find the number of C6H6 molecules, we can use Avogadro's number and the number of moles of xylene: (9.033 × 10^24 mol)(6.022 × 10^23 molecules/mol) = 5.442 × 10^48 molecules of C6H6.
User James Chien
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