Final answer:
The predominant decay mode of He (0*)+ Li2(1+) + ß+7A is Beta decay.
Step-by-step explanation:
The predominant decay mode of He (0*)+ Li2(1+) + ß+7A is Beta decay. Beta decay is a common mode of radioactive decay in which a nucleus emits beta particles. In this case, the beta decay results in the formation of a new nucleus with a higher atomic number than the original nucleus.