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What value(s) of 'b' will cause the quadratic equation 4x² + bx + 25 = 0 to have one real solution?

A) b = -20
B) b = -50
C) b = 20
D) b = 100

User Karlo
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1 Answer

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Final answer:

The values of 'b' that will cause the quadratic equation 4x² + bx + 25 = 0 to have one real solution are b = -20 and b = 20.

Step-by-step explanation:

A quadratic equation of the form at² + bt + c = 0 has one real solution if and only if the discriminant, b² - 4ac, equals zero. In this case, the given equation is 4x² + bx + 25 = 0. Comparing this equation with the general form, we have a = 4, b = b, and c = 25. Therefore, for one real solution, we need the discriminant to be zero:

b² - 4ac = 0

Substituting the values, we get:

b² - 4(4)(25) = 0

Simplifying further, we have:

b² - 400 = 0

Adding 400 to both sides, we get:

b² = 400

Taking the square root of both sides, we get:

b = ±20

Therefore, the values of 'b' that will cause the quadratic equation to have one real solution are b = -20 and b = 20.

User EFL
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