Abiha covers 280 meters in 350 steps, assuming a constant proportion of steps to distance based on her initial walk.
Let's set up a proportion:

![= \frac{\text{Number of steps 2}}{\text{Distance 2}} \]](https://img.qammunity.org/2024/formulas/mathematics/high-school/27gozrljnj1y19rbdc3xcb1a536q6ei5v2.png)
Given that Abiha takes 200 steps to cover 160 meters:
![\[ (200)/(160) = \frac{350}{\text{Distance 2}} \]](https://img.qammunity.org/2024/formulas/mathematics/high-school/kb854e2s0jlp5ax1e4jxaaryokvl44tkrj.png)
Now, we can solve for Distance 2:
![\[ \text{Distance 2} = (350 * 160)/(200) \]](https://img.qammunity.org/2024/formulas/mathematics/high-school/moekx34uwygje3wp36y24dr6hpy8v06d68.png)
![\[ \text{Distance 2} = 280 \, \text{meters} \]](https://img.qammunity.org/2024/formulas/mathematics/high-school/bnf0o455bdcp94rcsegosvq0asmeb3z5xb.png)
Therefore, Abiha would cover a distance of 280 meters in 350 steps based on the assumed constant proportionality between the number of steps and the distance covered. It's important to note that this assumes a linear relationship and doesn't account for factors like stride length variations or changes in walking speed.