Final answer:
The solutions to the equation -tanA = -1 within the domain 0 ≤ x ≤ 2π are at A = π/4 and A = 5π/4, corresponding to the points where the tangent function equals 1 within the first and third quadrants respectively.
Step-by-step explanation:
The student is asked to find the solution set of the given equation -tanA = -1 where A is between 0 and 2π radians. The equation -tanA = -1 simplifies to tanA = 1, since the negatives cancel out. We know that the tangent function is positive in the first and third quadrants and is equal to 1 at an angle of π/4 radians. However, since the tangent function has a period of π, another solution within the range exists at an angle π radians greater than π/4, which is 5π/4 radians. Therefore, the correct solution set for the equation within the given domain is (π/4, 5π/4).