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Given that x^2:(20-3x)=1:2. Find the possible values of x. Write your final answers as x....,....

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Final answer:

This quadratic equation using the quadratic formula to find the possible values of x as -10 and 4.

Step-by-step explanation:

To solve the equation x^2:(20-3x)=1:2, we can start by cross multiplying:

x^2 = 2(20 - 3x)

Expanding and simplifying:

x^2 = 40 - 6x

Bringing all terms to one side:

x^2 + 6x - 40 = 0

Now we can solve this quadratic equation by factoring, completing the square, or using the quadratic formula. Let's use the quadratic formula:

x = (-6 ± √(6^2 - 4(1)(-40)))/(2(1))

Simplifying further:

x = (-6 ± √(36 + 160))/2

x = (-6 ± √196)/2

x = (-6 ± 14)/2

So the possible values of x are -10 and 4.

User Bsekula
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