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What is the axis of symmetry of h(x)=5x²+40x+64?

a) x=-16
b) x=-4
c) x=4
d) x=16

User Jeffrey
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1 Answer

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Final answer:

The axis of symmetry of the quadratic function h(x)=5x²+40x+64 is found using the formula x = -b/(2a), resulting in x = -4, which corresponds to option b.

Step-by-step explanation:

The axis of symmetry for the quadratic function h(x) = 5x² + 40x + 64 can be found using the formula x = -b/(2a), where a and b are the coefficients from the quadratic function in the standard form ax² + bx + c. Here, a = 5 and b = 40. Plugging these values into the formula gives us the axis of symmetry as x = -40/(2*5) = -40/10 = -4. Therefore, the correct answer is b) x = -4.

User Shahabvshahabi
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