Final answer:
To find the amount of BaSO formed when BaCl₂ is added to Na₂SO₄, we can use stoichiometry. By calculating the number of moles of BaCl₂ and using the stoichiometry of the reaction, we can determine the amount of BaSO₄ formed. The mass of BaSO₄ formed is approximately 56.4 grams.
Step-by-step explanation:
To find the amount of BaSO₄ formed, we can use the concept of stoichiometry. The balanced equation for the reaction is:
BaCl₂(aq) + Na₂SO₄(aq) → BaSO₄(s) + 2NaCl(aq)
From the equation, we can see that 1 mole of BaCl₂ reacts with 1 mole of Na₂SO₄ to form 1 mole of BaSO₄. Given the concentrations and volumes of the two solutions, we can calculate the number of moles of BaCl₂ and Na₂SO₄ used in the reaction. Based on the limiting reactant, the amount of BaSO₄ formed can be determined.
Using the volume and concentration of BaCl₂, we can calculate the number of moles of BaCl₂:
Moles of BaCl₂ = (Volume of BaCl₂) * (Concentration of BaCl₂)
Next, we use the stoichiometry of the reaction to determine the number of moles of BaSO₄ formed:
Moles of BaSO₄ = Moles of BaCl₂
Finally, we can calculate the mass of BaSO₄ formed:
Mass of BaSO₄ = (Moles of BaSO₄) * (Molar mass of BaSO₄)
Plugging in the values, the mass of BaSO₄ formed is approximately 56.4 grams. Therefore, the correct answer is c. 56.4 g.