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Evaluate the expression: (7y^3/5 times 6x+5/21y).

a. (2y(6x+5)/15)
b. (14xy^2 + 5/105)
c. (2(6x+5)/15)
d. (7xy^2 + 5/105)

User Soundlink
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1 Answer

1 vote

Final answer:

To evaluate the expression (7y^3/5 * 6x+5/21y), you first simplify the expression inside the parentheses. Then, you multiply the numerator and denominator of the fraction by 7 to eliminate the fraction. Finally, you cancel out the y terms and simplify the expression to get the correct answer.

Step-by-step explanation:

To evaluate the expression (7y^3/5 * 6x+5/21y), we can simplify it step by step.

First, simplify the expression inside the parentheses.

6x+5/21y can be written as (6x+5)/(21y).

Then, multiply the numerator and denominator of the fraction by 7 to eliminate the fraction. We get:

(7y^3/5) * (7(6x+5)/(21y)) = (49y^3(6x+5))/(35*21y).

Cancel out the y terms:

(49y^2(6x+5))/(35*21) = (6x+5)/(15).

So the correct answer is $(c) (2(6x+5)/15)$.

User Ali Yesilli
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