Final answer:
The measure of the exterior angle at vertex B in an isosceles triangle is 125°.
Step-by-step explanation:
The measure of an exterior angle at vertex B in an isosceles triangle is equal to the sum of the measures of the two non-adjacent interior angles. In this case, the vertex angle A measures 70°, so the other two interior angles measure (180° - 70°)/2 = 55° each. Therefore, the measure of the exterior angle at B is 55° + 70° = 125°.