Question

Calculate the number of atoms of H and S present in 0.6 mol H₂S (Avogadro's number = 6.022 x 10²³).

a) Number of H atoms = ____
b) Number of S atoms = ____

Answer 1

To calculate the number of atoms of H and S present in 0.6 mol of H2S, we can use Avogadro's number. There are 7.224 x 10^23 H atoms and 3.611 x 10^23 S atoms.

Step-by-step explanation:

To calculate the number of atoms of H and S present in 0.6 mol H2S, we can use Avogadro's number. Avogadro's number is 6.022 x 10^23, which represents the number of atoms or molecules in one mole of a substance. In H2S, there are 2 moles of H atoms for every mole of H2S and 1 mole of S atoms for every mole of H2S.

a) Number of H atoms = 0.6 mol H2S * (2 mol H atoms / 1 mol H2S) * (6.022 x 10^23 H atoms / 1 mol H atoms)

= 7.224 x 10^23 H atoms

b) Number of S atoms = 0.6 mol H2S * (1 mol S atoms / 1 mol H2S) * (6.022 x 10^23 S atoms / 1 mol S atoms)

= 3.611 x 10^23 S atoms