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5 votes
Statements:

AC bisects ∠BCD

Reasons:
Given: ∠DI = ∠AD
Given: AC bisects ∠BCD
Given: DC = AD
Given: BC = AB

Prove:
#CDC
AC = AC

User RedFog
by
7.6k points

1 Answer

5 votes

Final answer:

The question is regarding a geometric proof to show that segment AC is congruent to itself, which is a direct application of the reflexive property in geometry, stating that any geometric figure is congruent to itself.

Step-by-step explanation:

The student is asking to prove a geometrical statement, specifically that segment AC is congruent to itself, which is a principle known as the reflexive property in geometry. The given information includes that AC bisects ∠BCD, various other angle and side congruences, and that the aim is to demonstrate a property of triangle congruence or segment equality.

In order to provide a proof, we can apply the concept of the reflexive property of equality in geometry, which states that any geometric figure is congruent or equal to itself. In this context, segment AC is congruent to AC by the reflexive property, as something is always equal to itself, and this can be applied to segments, angles, and other geometric figures.

When considering terms like angle of incidence and similar triangles, these are likely to be part of a broader geometric proof or explanation, where the properties of triangles, angles, and congruence are applied to illustrate or prove a particular geometric theorem or property.

User Mononofu
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8.1k points