Final answer:
The bond between Na-F is ionic, C-O is polar covalent, and F-F is nonpolar covalent. This determination is based on the electronegativity differences between the bonded atoms, with different ranges indicating if a bond is ionic, polar covalent, or nonpolar covalent.
Step-by-step explanation:
To identify the bond types in Na-F, C-O, and F-F, we look at the electronegativity difference between the atoms. The type of bond formed between two atoms is largely determined by this difference, categorizing bonds as nonpolar covalent, polar covalent, or ionic. Generally, a nonpolar covalent bond is formed if the electronegativity difference is less than 0.5, a polar covalent bond if the difference is between 0.5 to 1.9, and an ionic bond if the difference is more than 1.9.
The bond between Na and F is an ionic bond, as sodium (Na) is a metal and fluorine (F) is a nonmetal, and their electronegativity difference is greater than 1.9. The bond between carbon (C) and oxygen (O) is a polar covalent bond as these two nonmetals have an electronegativity difference between 0.5 and 1.9. Lastly, the F-F bond is a nonpolar covalent bond because both atoms have the same electronegativity, rendering their difference zero.
Therefore, the correct answer is d) Na-F (ionic) C-O (polar covalent) F-F (nonpolar covalent).