Question

You go scuba diving. How much greater is the pressure 99 m below the surface of the water than the pressure at the surface of the water? (Use rho = 1 g/cm³ = 1000 kg/m³)

a) 97,020 Pa
b) 980,200 Pa
c) 981,000 Pa
d) 9,800,200 Pa

Answer 1

The pressure 99 m below the surface of the water is 970,200 Pa.

Step-by-step explanation:

The pressure at a depth beneath the surface of the water is greater than the pressure at the surface due to the weight of the water above it. We can calculate the pressure using the formula p = ρgh, where p is the pressure, ρ is the density of water, g is the acceleration due to gravity, and h is the depth. In this case, the depth is 99 m and the density of water is 1000 kg/m³. Plugging these values into the formula, we get:

p = (1000 kg/m³) * (9.81 m/s²) * (99 m) = 970,200 Pa

So the pressure 99 m below the surface of the water is 970,200 Pa.