Final answer:
The theoretical probability of the arrow not stopping on a three or a four both times when the spinner is spun twice is 1/9.
Step-by-step explanation:
To find the theoretical probability that the arrow will not stop on a three or a four both times when the spinner is spun twice, we need to determine the number of favorable outcomes and the total number of possible outcomes.
Since the spinner has six equally likely outcomes, the probability of not stopping on a three or a four on one spin is 2/6, or 1/3. The probability of this happening on two consecutive spins is calculated by multiplying the individual probabilities together: 1/3 * 1/3 = 1/9.
Therefore, the theoretical probability of the arrow not stopping on a three or a four both times is 1/9, which is not one of the answer choices given. So, the correct answer is not listed.