Question

A car is travelling at 90 km per hour. Breaks are applied so as to produce a uniform acceleration of - 0.5 m/². Find how far will the car go before it is brought to rest

a) 8100 m
b) 16200 m
c) 32400 m
d) 4050 m

Answer 1

To find the distance the car will travel before it is brought to rest, we need to convert the initial speed from km/h to m/s and use the equation for uniformly accelerated motion.

Step-by-step explanation:

To find the distance the car will travel before it is brought to rest, we need to first convert the initial speed from km/h to m/s. We know that 1 km/h is equal to 0.2778 m/s. So, the initial speed of the car is 90 km/h x 0.2778 m/s = 25 m/s.

Next, we can use the equation for uniformly accelerated motion: d = (v^2 - u^2) / (2a), where d is the distance, v is the final velocity, u is the initial velocity, and a is the acceleration.

Since the car is brought to rest, the final velocity is 0 m/s. Plugging in the values, we get: d = (0^2 - 25^2) / (2 * -0.5) = -625 / -1 = 625 m.

Therefore, the car will travel 625 meters before it is brought to rest.