Question

An extra strength antacid tablet contains 750 mg of the active ingredient, CaCO₃. If it takes 22.25 mL of HCl(aq) to neutralize the tablet, how strong is the acid?

2HCl(aq)+CaCO₃ (aq)→CaCl₂(aq)+H₂O(l)+CO₂(g)

A. 0.0336 M

B. 0.0672 M

C. 0.1008 M

D. 0.1500 M

Answer 1

The strength of the acid is 90.08 M.

Step-by-step explanation:

The strength of the acid can be determined by calculating the concentration of HCl(aq). The balanced chemical equation shows that 2 moles of HCl react with 1 mole of CaCO₃, so we can calculate the number of moles of HCl using the volume and concentration.

First, convert the volume of HCl to liters: 22.25 mL = 0.02225 L.

Then, calculate the concentration of HCl: 2 moles HCl / 0.02225 L HCl = 90.08 M. Therefore, the acid strength is 90.08 M.