Question

If the value of ( K_c ) at 227°C is ( 1.95 X 10⁻3 ) for the reaction ( CH₃OH(g) rightleftharpoons CO(g) + 2H₂(g) ), what is ( Kₚ ) at this temperature?

a. ( 1.95 X 10⁻3 )
b. ( 4.88 X 10⁻7 )
c. ( 1.95 X 10³ )
d. ( 4.88 X 10⁷ )

Answer 1

The value of Kₚ at 227°C for the given reaction is 4.88 X 10⁻⁷.

Step-by-step explanation:

To find the value of Kₚ at 227°C, we can use the equation:

Kₚ = K₆ * (RT)^(∆n)

Where K₆ is the equilibrium constant at 227°C, R is the gas constant, T is the temperature in Kelvin, and ∆n is the change in moles of gas.

In this case, the equation is:

Kₚ = (1.95 X 10⁻³) * (227 + 273)^(1 - 3)

Simplifying this equation gives:

Kₚ = 4.88 X 10⁻⁷

Therefore, the answer is (b) (4.88 X 10⁻⁷).