Final answer:
The shunt resistance in order to pass 1% of the main current in a galvanometer with resistance (Rg) is equal to 99 times the resistance of the galvanometer (Rs = 99Rg).
Step-by-step explanation:
In order to pass 1% of the main current in a galvanometer with resistance (Rg), the shunt resistance would be equal to 99 times the resistance of the galvanometer.
This can be represented as Rs = 99Rg.
For example, if the galvanometer has a resistance of 1 ohm (Rg = 1), then the shunt resistance would be 99 ohms (Rs = 99 x 1).