Question

What is the ΔH for O2(g) in the reaction of glucose with oxygen: C_6H_12O_6(s) + 6O_2(g) → 6CO_2(g) + 6H_2O_(l)?

a) -393.5 kJ/mol

b) -285.83 kJ/mol

c) 0 kJ/mol

d) 1,273.02 kJ/mol

Answer 1

The enthalpy change for the reaction C6H12O6(s) + 6O2(g) → 6CO2(g) + 6H2O(l) is -2802.5 kJ/mol.

Step-by-step explanation:

The enthalpy change for the combustion of glucose to carbon dioxide and water is the sum of the enthalpy changes for the conversion of glucose and oxygen to the elements (+1273.3 kJ) and for the conversion of the elements to carbon dioxide and water (-4075.8 kJ). Therefore, the overall enthalpy change for the reaction C6H12O6(s) + 6O2(g) → 6CO2(g) + 6H2O(l) is -2802.5 kJ/mol.