Question

Use the reaction below to answer the question that follows. a.b.c.2Al(s)+32O₂(g)⟶Al2O₃(s)ΔH=−1676 kJ₂Fe(s)+32O₂(g)⟶Fe₂O₃(s)ΔH=−824 kJFe₂O₃(s)+2Al(s)⟶Al₂O₃(s)+2Fe(s) Calculate the change in enthalpy, in kilojoules for reaction c above.

a) -852 kJ
b) -852 kJ
c) -852 kJ
d) -852 kJ

Answer 1

The change in enthalpy for reaction c can be calculated by summing the enthalpy changes for reactions a and b. The values for these reactions are -838 kJ/mol of Al and -412 kJ/mol of Fe, respectively. Therefore, the change in enthalpy for reaction c is -1250 kJ.

Step-by-step explanation:

The change in enthalpy for reaction c can be calculated by using the values of enthalpy changes for reactions a and b. First, we need to find the enthalpy change for reaction a by dividing -1676 kJ by 2 (since 2 mol of Al are consumed). This gives us -838 kJ/mol of Al. Then, we need to find the enthalpy change for reaction b by dividing -824 kJ by 2 (since 2 mol of Fe are consumed). This gives us -412 kJ/mol of Fe. Finally, we can calculate the change in enthalpy for reaction c by summing the enthalpy changes for reactions a and b: -838 kJ/mol of Al + -412 kJ/mol of Fe = -1250 kJ.