Question

Mass of Mg: 0.079 g

Volume of H2 gas: 82.0 ml
Temperature of H2 gas: -23°C
Atmospheric Pressure: 762 mm Hg
Vapor pressure of water: 18 mm Hg
Calculate the corrected volume of H2 gas at STP.

a. 82.0 ml
b. 64.0 ml
c. 100.0 ml
d. 82.0 ml

Answer 1

To calculate the corrected volume of hydrogen gas at STP, we can use the combined gas law equation. Given the initial volume, temperature, atmospheric pressure, and vapor pressure of water, we can substitute the values into the equation to find the corrected volume.

Step-by-step explanation:

To calculate the corrected volume of hydrogen gas at STP, we can use the combined gas law equation. The equation is as follows:

V₂ = (V₁ x P₂ x T₁) / (P₁ x T₂)

Given the following values:

V₁ = 82.0 ml

P₁ = atmospheric pressure - vapor pressure of water = 762 mmHg - 18 mmHg = 744 mmHg

T₁ = -23°C + 273.15 = 250.15 K

P₂ = 760 mmHg

T₂ = 273.15 K

Substituting these values into the equation, we get:

V₂ = (82.0 ml x 760 mmHg x 250.15 K) / (744 mmHg x 273.15 K) = 64.0 ml

Therefore, the corrected volume of H2 gas at STP is 64.0 ml. Answer choice (b) is correct.