Question

A chemist dissolves crystals of an unknown substance into water at room temperature. He found that 33 g of the substance can be dissolved into a hundred milliliters of water. What property of the unknown substance was it Kim is most like?

a. Solubility
b. Density
c. Boiling point
d. Conductivity

Answer 1

The unknown substance is most likely similar to solubility.

Step-by-step explanation:

b. Solubility

To find the mass of solute in 100 mL of solution, we assume that the density of this dilute solution is the same as the density of water because of the low solubility of the salt, so that 100 mL of water gives 100 mL of solution. We can then determine the amount of salt that dissolves in 100 mL of water:

Solubility = Mass of solute/Volume of solvent

Solubility = 33 g/100 mL = 0.33 g/mL

Therefore, the property of the unknown substance that it is most like is solubility.