Final answer:
The correct solutions for the equation 93=20t−16t² using the quadratic formula are t = 7/4 and t = 3. Neither of these solutions match the options provided in the question.
Step-by-step explanation:
To solve the equation 93=20t−16t², we first need to express it in the standard form by rearranging the terms to get 0 on one side of the equation:
16t² - 20t + 93 = 0
Now, we can use the quadratic formula, −b ± √b² - 4ac / 2a, to find the values of t.
In our equation, a = -16, b = 20, and c = 93. Plugging these values into the quadratic formula we get:
t = −(20) ± √(20)² - 4(-16)(93) / 2(-16)
Simplifying under the radical we have:
t = −(20) ± √400 + 5952 / -32
t = −(20) ± √6352 / -32
t = −(20) ± 79.7 / -32
Now, we find the two possible solutions for t:
t = (−20 + 79.7) / -32 ≈ 7/4
t = (−20 − 79.7) / -32 ≈ 3
So the two solutions are t = 7/4 or t = 3. Option B) t = 3 or t = −7/4 is incorrect because of the minus sign. Hence, the correct answer is not listed in the options provided.