Final answer:
The maximum height reached by the arrow can be determined by using the projectile motion equations, factoring in the vertical component of the initial velocity and the acceleration due to gravity. Unfortunately, the question does not provide enough information to ascertain the correct answer among the given choices, such as the initial velocity or angle of projection specific to the question.
Step-by-step explanation:
To determine the maximum height reached by the arrow, we need to consider the vertical component of the initial velocity. Since the arrow is shot upward at an angle, its vertical velocity component is determined by the initial speed and the angle of projection. The relevant equation for vertical motion is:
vf^2 = vi^2 + 2a * d
where vf is the final velocity (which is 0 at the maximum height), vi is the initial vertical velocity, a is the acceleration due to gravity (which is -9.81 m/s^2, since gravity acts downward), and d is the maximum height reached.
Using the given initial velocity of 30 m/s and the angle of 60 degrees, the initial vertical velocity component is:
vi = 30 m/s * sin(60)
Using the formula and solving for d, we get the maximum height reached, and by integrating the vertical velocity with respect to time, we can obtain the time at which this maximum height is reached.
However, the provided options are seemingly part of a multiple-choice question where the full calculation details are not given. Therefore, without the necessary information to calculate the correct answer, I cannot confidently confirm which of the given options, if any, are accurate.