Answer:
G. 118°
Explanation:
Imagine a line, parallel to AD, that passes through B to a point x on the line CD.
∠CBX=∠CAD=28 (corresponding angles)
∠EBX=90 (BX║ED, BE║XD)
∠CBE=∠CBX+EBX
∠CBE=28+90
∠CBE=118°
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