Final answer:
The probability of getting a total sum more than 10 when rolling two fair six-sided dice is 1/12. This is calculated by identifying the three combinations that yield totals of 11 or 12 out of the 36 possible outcomes when rolling two dice.
Step-by-step explanation:
The question asks for the probability of getting a total sum more than 10 when rolling two fair six-sided dice. To find this, we look at the possible sums that are more than 10, which are 11 and 12. The combinations that give us a sum of 11 are (5, 6) and (6, 5), and the combination that gives us a sum of 12 is (6, 6). There are a total of 6 x 6 = 36 possible outcomes when rolling two dice. Therefore, there are 3 favorable outcomes that result in a sum more than 10.
Using the probability formula P(E) = Number of favorable outcomes / Total number of possible outcomes, we can calculate:
P(getting a total more than 10) = 3 / 36 = 1/12.
Therefore, the correct answer is C. 1/12.