Question

Sec A =m sq+n sq/2mn then fing whole root 1+sin A/1-sinA​

Answer 1

To find the value of √(1+sin A)/(1-sin A), use the given equation sec A = (m^2+n^2)/(2mn) and solve for sin A. Substitute sin A into the expression and simplify if needed.

Step-by-step explanation:

To find the value of √(1+sin A)/(1-sin A), we need to use the given equation sec A = (m^2+n^2)/(2mn). From this equation, we can solve for sin A and substitute it into the expression. Here are the steps:

1. Start with the equation sec A = (m^2+n^2)/(2mn).
2. Take the reciprocal of both sides to get cos A = (2mn)/(m^2+n^2).
3. Use the Pythagorean trigonometric identity sin^2 A + cos^2 A = 1 to solve for sin A. Substitute cos A from the previous step and solve for sin A.
4. Substitute sin A into the expression √(1+sin A)/(1-sin A).
5. Simplify the expression further if needed.