Question

A pair of charged conducting plates produces a uniform field of 12,000N/C between the plates. The separation of the plates is 40 mm. An electron is projected from plate A, directly toward plate B, with an initial velocity of ___. The distance of closest approach of the electron to plate B is nearest to ___.

Answer 1

The initial velocity of the electron projected from plate A is 480 m/s. The distance of closest approach to plate B cannot be determined without additional information.

Step-by-step explanation:

To calculate the initial velocity of the electron projected from plate A, we can use the formula:

v = E*d

Where v is the initial velocity, E is the electric field strength (12,000 N/C), and d is the separation of the plates (40 mm = 0.04 m).

Plugging in the values, we get:

v = (12,000 N/C) * (0.04 m) = 480 m/s

The distance of closest approach of the electron to plate B can be calculated using the equation:

r = (q * V) / (m * v^2)

Where r is the distance of closest approach, q is the charge of the electron, V is the potential difference between the plates, m is the mass of the electron, and v is the initial velocity. However, the given question does not provide values for q, V, and m, so we cannot calculate the exact distance of closest approach without that information.