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It is known that there are 7 acceptable products and 3 defective products out of 10 transistors. Each time, an inspector picks one product by random and test it. After the test, that product is marked and put aside. The inspector will keep testing until he is able to determine which three are defective. What is the probability that the inspector has tested 7 times in total? now

User Dlanced
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Final answer:

To find the probability that the inspector has tested 7 times in total, we can use the geometric distribution. The formula for geometric distribution is P(X = k) = (1 - p)^(k-1) * p, where X is the number of trials needed to find the first success, p is the probability of success, and k is the desired number of trials. By substituting the given values and solving the equation, we find that the probability is 0.021.

Step-by-step explanation:

To solve this problem, we can use the concept of geometric distribution. The geometric distribution is used to model the number of trials needed to get the first success in a sequence of independent Bernoulli trials. In this case, the success is finding a defective product and the trials are the number of random picks.

Let's define X as the number of trials needed to find the first defective product. We want to find P(X = 7), which is the probability that the inspector has tested 7 times in total.

Using the formula for geometric distribution, we have P(X = 7) = (1 - p)^(7-1) * p, where p is the probability of picking a defective product.

Given that there are 7 acceptable products and 3 defective products out of 10 transistors, the probability of picking a defective product is p = 3/10.

Substituting p = 3/10 into the formula, we can calculate P(X = 7) as (1 - 3/10)^(7-1) * (3/10) = 0.021 (rounded to three decimal places).

User Ghanshyam Katriya
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