Final answer:
To determine how many grams of MgCl2 will be produced, one must perform a stoichiometry calculation using the balanced chemical equation and the molar masses of Mg(OH)2, HCl, and MgCl2.
Step-by-step explanation:
The student is asking how many grams of MgCl2 will be produced from a given amount of Mg(OH)2 and HCl. To solve this, we must perform a stoichiometry calculation.
The balanced chemical equation for the reaction is:
Mg(OH)2 (s) + 2HCl (aq) → MgCl2 (aq) + 2H2O (l).
First, we find the molar mass of Mg(OH)2 (58.32 g/mol) and HCl (36.46 g/mol). Then we convert the given masses of Mg(OH)2 and HCl to moles, and find which is the limiting reactant. This reactant will determine the maximum amount of MgCl2 that can be produced.
The molar mass of MgCl2 is 95.21 g/mol. Using the limiting reactant, we calculate the moles of MgCl2 that can be formed, and finally convert this to grams to find the mass of MgCl2 produced.