Question

Balance the following redox reaction in an acid solution, using the half-reaction method. BrO3- (aq) + NO2(aq) -> Br-(aq) + NO3-(aq)

Answer 1

To balance the redox reaction BrO3- (aq) + NO2(aq) -> Br-(aq) + NO3-(aq) in an acid solution, you can use the half-reaction method. Here are the steps: 1) Determine the oxidation numbers. 2) Balance the atoms other than oxygen and hydrogen. 3) Balance the oxygen atoms. 4) Balance the hydrogen atoms. The balanced equation is BrO3- (aq) + 3NO2(aq) + 6H+(aq) -> 3Br-(aq) + 3NO3-(aq) + 3H2O(l).

Step-by-step explanation:

To balance the redox reaction BrO3- (aq) + NO2(aq) -> Br-(aq) + NO3-(aq) in an acid solution, you can use the half-reaction method. Here are the steps:

1. First, determine the oxidation numbers for each element in the equation. In this case, Br is being reduced and has an oxidation number of -1, while N is being oxidized and has an oxidation number of +3.
2. Next, balance the atoms other than oxygen and hydrogen. Start with the element that is changing oxidation state, in this case, N and Br. Since there is one atom of N on both sides of the equation, we can move to balancing Br. There are three Br atoms on the left side and only one on the right side. To balance it, multiply the Br- on the right side by three.
3. Now, balance the oxygen atoms. There are three oxygen atoms on the left side and four on the right side. To balance it, add water (H2O) molecules on the right side to match the oxygen atoms on the left side (three water molecules in this case).
4. Finally, balance the hydrogen atoms. There are six hydrogen atoms on the left side and two on the right side. To balance it, add H+ ions on the left side to match the hydrogen atoms on the right side (six H+ ions in this case).

The balanced equation for the redox reaction in an acid solution is: BrO3- (aq) + 3NO2(aq) + 6H+(aq) -> 3Br-(aq) + 3NO3-(aq) + 3H2O(l).