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In a certain lottery, 48 balls numbered 1 through 48 are placed in a machine and six of them are drawn at random.

a) If in this lottery, the order the numbers are drawn in doesn’t matter, compute the probability that you win the million-dollar prize if you purchase a single lottery ticket.
b) Answer questions a) and b) assuming that you purchase ten tickets.
c) You have a ticket with five numbers exactly those you need to win the lottery. What is the probability to win in this case?

User Amr Ali
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Final answer:

In this lottery, the probability of winning the million-dollar prize with a single ticket, ten tickets, and a ticket that matches 5 numbers is calculated using binomial coefficients.

Step-by-step explanation:

In this lottery, there are 48 balls numbered 1 through 48, and 6 of them are drawn at random without replacement. Let's solve the questions step by step:

a) If the order of the numbers doesn't matter, we need to find the probability of choosing the winning combination of 6 numbers out of 48. The number of ways to choose 6 numbers out of 48 is given by the binomial coefficient C(48, 6) = 48!/(6!(48-6)!). The total number of possible outcomes is given by the number of ways to choose any 6 numbers out of 48, which is C(48, 6). Therefore, the probability of winning the million-dollar prize with a single lottery ticket is 1/C(48, 6).

b) If you purchase 10 tickets, the probability of winning the million-dollar prize with one of the tickets is 10 times the probability calculated in part (a). Therefore, the probability is 10/C(48, 6).

c) If you have a ticket with 5 numbers that exactly match the winning combination, we need to find the probability of choosing the remaining 48-5 = 43 numbers in the correct order. The probability of choosing the correct 43 numbers is 1/C(43, 6). Therefore, the probability of winning in this case is 1/C(43, 6).

User Nass
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