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Let f(x) = 3 − 15, F(X) = 4, and h(x) = 0.5(6)^x.

a.) Find the rate of change for each over the interval [1, 4].
b.) Which function has the greatest rate of change over that interval?
c.) Which function has the least rate of change over that interval?

User Ninad
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Final answer:

The rate of change for the constant functions f(x) and F(x) is 0, while the rate of change for the exponential function h(x) over the interval [1, 4] is 215. Therefore, h(x) has the greatest rate of change, and both f(x) and F(x) have the least rate of change.

Step-by-step explanation:

The student has been provided with three functions and is asked to find the rate of change for each over the interval [1, 4], to identify which function has the greatest and least rate of change. The functions given are:

  • f(x) = 3 - 15, which simplifies to f(x) = -12, a constant function.
  • F(x) = 4, another constant function.
  • h(x) = 0.5(6)^x, an exponential function.

For the constant functions f(x) and F(x), the rate of change over any interval is 0 because they are horizontal lines.

For the exponential function h(x), the rate of change is not constant, so it must be evaluated:

  1. Calculate h(1) = 0.5(6)^1 = 3.
  2. Calculate h(4) = 0.5(6)^4 = 0.5(1296) = 648.
  3. Find the average rate of change over the interval [1, 4] by subtracting h(1) from h(4) and dividing by the change in x: (648 - 3) / (4 - 1) = 645 / 3 = 215.

The greatest rate of change is for h(x) and the least rate of change is for both f(x) and F(x) since they are the same at 0.

User Karin
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