Final answer:
To find out how much heat is produced when 150 grams of oxygen gas are consumed in the combustion of ethane, we need to use the balanced equation and the enthalpy change given in the question. By calculating the number of moles of oxygen gas and ethane that react, we can determine the amount of heat produced. The result is approximately 1.92 × 10³ kJ.
Step-by-step explanation:
To find out how much heat is produced when 150 grams of oxygen gas are consumed in the combustion of ethane, we need to use the balanced equation and the enthalpy change given in the question. From the balanced equation, we know that 5 moles of oxygen gas are required to react with 1 mole of C₃H₈. Using the molar mass of O₂ (32 g/mol), we can calculate the number of moles of oxygen gas in 150 grams:
Moles of O₂ = mass of O₂ / molar mass of O₂ = 150 g / 32 g/mol = 4.69 mol
Since the balanced equation tells us that 1 mole of C₃H₈ reacts with 5 moles of O₂, we can calculate the moles of C₃H₈ that react:
Moles of C₃H₈ = Moles of O₂ / 5 = 4.69 mol / 5 = 0.94 mol
Finally, using the given enthalpy change, we can calculate the amount of heat produced:
Heat = moles of C₃H₈ × enthalpy change = 0.94 mol × 2.04 x 10³ kJ/mol = 1.92 x 10³ kJ
Therefore, the amount of heat produced when 150 grams of oxygen gas are consumed is approximately 1.92 × 10³ kJ.