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Numbers a, b, c and d are four consecutive odd numbers. Which statement must be true?

a. The sum a + b + c + d is 12 greater than a
b. The sum a + b + c + d is 6 greater than a
c. The differences b – a and d – c are always equal
d. The differences c – b and d – a are always equal

1 Answer

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Final answer:

The correct statement for four consecutive odd numbers a, b, c, and d is that the differences b - a and d - c are always equal. This is because when expressed in terms of a, b = a + 2 and d = a + 6 while c = a + 4, thus making both differences equal to 2.

Step-by-step explanation:

Given that a, b, c, and d are four consecutive odd numbers, we can represent them as:

  • a = a
  • b = a + 2
  • c = a + 4
  • d = a + 6

Now to find out which statement must be true:

  • a. The sum a + b + c + d is 12 greater than a
    Adding the numbers: a + (a + 2) + (a + 4) + (a + 6) = 4a + 12, which is 12 plus 3 times a, not just 12 greater than a. So, this statement is incorrect.
  • b. The sum a + b + c + d is 6 greater than a
    This does not follow from the sum we calculated, so it is also incorrect.
  • c. The differences ba and dc are always equal
    Since b = a + 2 and d = a + 6, c = a + 4, the difference ba = 2 and dc = 2. Hence, this statement is true.
  • d. The differences cb and da are always equal
    The difference cb = (a + 4) – (a + 2) = 2, but the difference da = (a + 6) – a = 6, which are not equal, therefore this statement is incorrect.

Therefore, the correct statement concerning the consecutive odd numbers is c. The differences ba and dc are always equal.

User Enrique Flores
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