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Which function has real zeros at x = -8 and x = -5?

A) g(x) = x² + 3x - 40
B) g(x) = x² + 3x + 40
C) g(x) = x² + 14x - 40
D) None of the above

User Ubiyubix
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1 Answer

6 votes

Final answer:

No given function has real zeros at both x = -8 and x = -5; the function with these zeros would be x² + 13x + 40, but this is not one of the options presented, so the answer is 'None of the above'.

Step-by-step explanation:

To find the function with real zeros at x = -8 and x = -5, you can use these zeros to create factors of the function. The factors associated with these zeros would be (x + 8) and (x + 5). When these two factors are multiplied together, they create a quadratic equation in the form of ax² + bx + c = 0.

To find which function matches with the given zeros, expand these factors:

(x + 8)(x + 5) = x² + 5x + 8x + 40

= x² + 13x + 40

The correct quadratic function that has real zeros at x = -8 and x = -5 is g(x) = x² + 13x + 40. However, this option is not listed. Therefore, the correct answer is D) None of the above.

User Michael Woolsey
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