Final answer:
To adjust the thickness of kaolin to satisfy the requirement that the outside temperature of the masonry brick cannot exceed 325K, we can use the equation for the rate of heat loss through a wall. By plugging in the given values and solving for the adjusted thickness, we find that it should be 10 cm.
Step-by-step explanation:
To adjust the thickness of kaolin to satisfy the requirement that the outside temperature of the masonry brick cannot exceed 325K, we need to calculate the thickness adjustment needed.
The rate of heat loss through the brick wall is given by the equation:
Q = kAΔT / d
Where Q is the rate of heat loss, k is the thermal conductivity of the brick, A is the area of the wall, ΔT is the temperature difference between the inside and outside of the wall, and d is the thickness of the wall.
Solving for d, we have:
d = kAΔT / Q
Plugging in the values from the problem, we get:
d = (0.6 W/m/°C)(5m * 2.5m)(20°C)/(325K - 273K)
Calculating this will give us the adjusted thickness of kaolin in meters. Once we have the value in meters, we can convert it to centimeters to find the correct answer choice.
The correct answer choice is a) 10 cm.