Question

After the code that follows is executed, the variable named userEntry will contain:

var userEntry = 461.95;
userEntry = parseInt(userEntry);
a) cannot tell
b) 461
c) 461.95
d) 462

Answer 1

The variable named userEntry will contain the integer value 461.

Step-by-step explanation:

After executing the code, the variable named userEntry will contain the integer value 461. This is because the parseInt() function in JavaScript converts a given value to an integer by removing any decimal places and only considering the whole number part.