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A body of mass (m=0.2 , kg) is attached to a spring (k=20 , N/m) and rests on a horizontal frictionless table. The spring is pulled to the right by a distance of (10 , cm) and pushed with a speed (S_m). What is the amplitude of the resulting oscillatory motion?

a) (10 , cm)

b) (20 , cm)

c) (5 , cm)

d) (15 , cm)

User Vanevery
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1 Answer

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Final answer:

The amplitude of the resulting oscillatory motion is 5 cm.

Step-by-step explanation:

To find the amplitude of the resulting oscillatory motion, we can use the equation:

Amplitude = displacement/2

Where displacement is the distance the spring is pulled or compressed. In this case, the spring is pulled to the right by a distance of 10 cm, so the displacement is 10 cm. Plugging this value into the equation, we get:

Amplitude = 10 cm / 2 = 5 cm

Therefore, the amplitude of the resulting oscillatory motion is 5 cm (option c).

User Charles Han
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