Question

Find the vertex of a quadratic function written in standard form
f(x)=x^2+2x-5

Answer 1

The vertex of the quadratic function in standard form can be found using the formula x = -b / (2a). For f(x) = x² + 2x - 5, the vertex is (-1, f(-1)).

Step-by-step explanation:

To find the vertex of a quadratic function in standard form, f(x) = ax² + bx + c, you can use the formula: x = -b/ (2a). In this case, the equation is f(x) = x² + 2x - 5, so a = 1, b = 2, and c = -5.

Substituting these values, we have x = - (2) / (2 * (1)) = -1.

Therefore, the vertex of the quadratic function is (x,y) = (-1, f(-1)).