Final answer:
The oxidation state of Fe in Mohr's salt is +2.
Step-by-step explanation:
The oxidation state of Fe in Mohr's salt (FeSO4·(NH4)2SO4·6H2O) is +2. In this compound, iron (Fe) is present as Fe2+ ions. The sulfate ion (SO4) has a charge of -2, and the ammonium ion ((NH4)2) has a charge of +2. To balance the charges, Fe must have a +2 oxidation state.