Question

The factors of the quadratic function f(x)=x^2 +6x−7 are (x+7) and (x−1). The y-intercept of the function is __________, and the zeros of the function are __________.

a) Y-intercept: 7, Zeros: -7, 1

b) Y-intercept: -7, Zeros: 7, -1

c) Y-intercept: -7, Zeros: -7, 1

d) Y-intercept: 7, Zeros: -7, -1

Answer 1

The y-intercept of the quadratic function is -7, and the zeros of the function are -7 and 1.

Step-by-step explanation:

The y-intercept of the quadratic function f(x) = x^2 + 6x - 7 is -7, since the y-intercept is the value of the function when x = 0. Substituting x = 0 into the function gives f(0) = (0)^2 + 6(0) - 7 = -7.

The zeros (also known as roots or x-intercepts) of the quadratic function are the values of x for which the function equals zero. Since the factors of the quadratic function are (x+7) and (x-1), the zeros of the function are x = -7 and x = 1.