29.6k views
3 votes
Find the coordinates of a point that divides a line segment AB in the ratio 2:6. A(-6,9) B(6,-7)

a) ((-2,3))
b) ((0,1))
c) ((2,-1))
d) ((4,-3))

User Belloc
by
7.3k points

1 Answer

3 votes

Final answer:

The point that divides the line segment AB in the ratio 2:6, with A(-6,9) and B(6,-7), is found using the section formula and has coordinates (-3,5), which is not listed in the given options.

Step-by-step explanation:

To find the coordinates of a point that divides a line segment AB in the ratio 2:6, we use the section formula. The coordinates of points A and B are given as A(-6,9) and B(6,-7). The section formula for a point (x, y) that divides a line segment AB in the ratio m:n is given by:

x = (mx2 + nx1) / (m + n)

y = (my2 + ny1) / (m + n)

Substituting the values, we get:

x = (2*6 + 6*(-6)) / (2 + 6) = (12 - 36) / 8 = -24 / 8 = -3

y = (2*(-7) + 6*9) / (2 + 6) = (-14 + 54) / 8 = 40 / 8 = 5

The coordinates of the point that divides the line segment AB in the ratio 2:6 is (-3,5), which is not one of the options provided. Therefore, there may be an error in the question or the provided options.

User Monster
by
8.6k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories