Final answer:
From 37 grams of Zn, you can form 72.93 grams of Zn₃(PO₄)₂.
Step-by-step explanation:
To calculate the amount of Zn₃(PO₄)₂ formed from 37 grams of Zn, we need to use the balanced chemical equation and the molar ratios. The balanced equation for the reaction is:
3 Zn + 2 H₃(PO₄) → Zn₃(PO₄)₂ + 3 H₂
From the equation, we can see that 3 moles of Zn reacts to form 1 mole of Zn₃(PO₄)₂. To determine the number of moles of Zn₃(PO₄)₂, we need to convert grams of Zn to moles using its molar mass:
37 g Zn * (1 mole Zn / 65.38 g Zn) = 0.566 moles Zn
Since the molar ratio is 3:1, we can calculate the number of moles of Zn₃(PO₄)₂:
0.566 moles Zn * (1 mole Zn₃(PO₄)₂ / 3 moles Zn) = 0.189 moles Zn₃(PO₄)₂
To convert moles of Zn₃(PO₄)₂ to grams, we use its molar mass:
0.189 moles Zn₃(PO₄)₂ * (386.13 g Zn₃(PO₄)₂ / 1 mole Zn₃(PO₄)₂) = 72.93 grams Zn₃(PO₄)₂