Question

A rocket was launched and its height, h, in metres, above the ground after time,

t, in seconds, is represented by h = 11 + 10t - 22. For how many seconds was
the rocket in the air?
a)about 6.64 s
b) about 6.27 s
c) about 5.93 s
d) about 7.35 s

Answer 1

The rocket was in the air for approximately 3.3 seconds.

Step-by-step explanation:

The equation h = 11 + 10t - 22 represents the height of a rocket above the ground after time t, in seconds. To find the time the rocket was in the air, we need to determine when the rocket reaches the ground. This happens when the height (h) is equal to 0. So we set the equation equal to 0 and solve for t:

11 + 10t - 22 = 0

10t - 11 = 22

10t = 33

t = 3.3 seconds

Therefore, the rocket was in the air for approximately 3.3 seconds.